Sorry late. :| ngayon ko lang naccess blogger.
anyways

S1. lim x->0- |X|/x
S2. lim x-> inf (2x^3+x-1)/(1-x^3)
S3. lim x->-inf x+1/x^2-4
S4. The equation of the VA of g(x)=3/x+1 is x=?
S5. lim x->-inf x^2-1/2-x
S6 lim t->4 t-4/(sqroot t)-2
S8 The eq. of the HA of f(x) 1-2x^2/x^2-1 is y=?
S9. lim x->-3- ||x||
S10 lim x->2- ( (3/x^2-4) - 1/x-2) )
S11 lim x->2 x^3-8/x-2
S12 lim x->-3- sqroot(x^2-9)
S13 lim x->-1 x+1/ (sqroot x+5) -4
S14 lim x->0 2/sqroot(x^2-4)
S15 lim x->3 (x+4)(x^2-9)/(x-3)(x^2-16)
S17. Find lim x->-inf f(x) when graph of f(x) is a line with + slope
S18. lim x->2 x^2-4/2-x
S19. lim x->-inf 24x^2-1/2x^2+3
S20. one of the VA of f(x)= x+2/x^2-3x-18 is x=?
S21. lim x->-inf 4x^3+2x^2-5/2x^3-8x^2+x
S22. lim x->-inf sqroot(x^2+1)/3-x
S23 if f(x)= x^2-9 if x !=0
9 if x=0
find lim x->0 f(x)

S24. let f(x)= x-3 sgn (x)
find lim x->0- f(x)


S26. the HA of g(x)=2-1/x is y=?
S27. lim x->1+ sqroot(x+1)/1-x
S28. lim x-> inf (5-4/x^3)
S29 lim x->-inf (3x+1/x^2)
S30. may drawing :))
find lim x->-inf g(x).
graph is semicircle, center at origin. to the right after the circle, straight line slanting to the right, to left of circle straight line slanting to left.

btw. |x| - absolute value, ||x||- GIF, lim x->2- means approaching 2 from left (right kung + ), x^2 is x raised to the 2nd power. etc. yay
e-luck :D

Sinong Mortal Enemy ni Optimus Proton? Eh di si Megaelectron O:
joke joke joke.